-4.9x^2-3.08x+5=0

Solution for -4.9x^2-3.08x+5=0 equation:

-4.9x^2-3.08x+5=0

a = -4.9; b = -3.08; c = +5;
Δ = b2-4ac
Δ = -3.082-4·(-4.9)·5
Δ = 107.4864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.08)-\sqrt{107.4864}}{2*-4.9}=\frac{3.08-\sqrt{107.4864}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.08)+\sqrt{107.4864}}{2*-4.9}=\frac{3.08+\sqrt{107.4864}}{-9.8}
$